How do I sort a dictionary by key or value?
To sort a dictionary by key in Python, you can use the sorted
function, like this:
d = {"a": 1, "b": 2, "c": 3}
sorted_d = sorted(d.items(), key=lambda x: x[0])
sorted_d
will now be a list of tuples, sorted by the key of each tuple.
If you want to sort the dictionary by value, you can use the following code:
d = {"a": 1, "b": 2, "c": 3}
sorted_d = sorted(d.items(), key=lambda x: x[1])
This will give you a list of tuples, sorted by the value of each tuple.
You can also use the OrderedDict
class from the collections
module to sort a dictionary by key or value. To do this, you can use the sorted
function to create a sorted list of keys or values, and then use the OrderedDict
constructor to create an OrderedDict
from the sorted list.
For example:
from collections import OrderedDict
d = {"a": 1, "b": 2, "c": 3}
sorted_d = OrderedDict(sorted(d.items(), key=lambda x: x[0]))
This will create an OrderedDict
with the keys sorted in ascending order.
You can also use the sort_by_key
and sort_by_value
functions from the dicttoolz
library to sort dictionaries by key or value, respectively.
from dicttoolz import sort_by_key, sort_by_value
d = {"a": 1, "b": 2, "c": 3}
sorted_d = sort_by_key(d)
This will return a new dictionary with the keys sorted in ascending order.
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