How do I split Python list into equally-sized chunks?
To split a list into equally sized chunks, you can use the grouper function from the itertools module.
Here's an example of how you can use it:
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)
# Example usage
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
n = 3
chunks = list(grouper(my_list, n))
print(chunks)
This will output the following list of chunks:
[(1, 2, 3), (4, 5, 6), (7, 8, 9), (10, None, None)]
You can also use list slicing to achieve the same result:
def split_list(my_list, chunk_size):
return [my_list[i:i + chunk_size] for i in range(0, len(my_list), chunk_size)]
# Example usage
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
chunk_size = 3
chunks = split_list(my_list, chunk_size)
print(chunks)
This will output the following list of chunks:
[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10]]
You can choose the method that best fits your needs.
This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
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