# How do I sort a dictionary by key or value?

To sort a dictionary by key in Python, you can use the `sorted` function, like this:

```python
d = {"a": 1, "b": 2, "c": 3}
sorted_d = sorted(d.items(), key=lambda x: x[0])
```

`sorted_d` will now be a list of tuples, sorted by the key of each tuple.

If you want to sort the dictionary by value, you can use the following code:

```python
d = {"a": 1, "b": 2, "c": 3}
sorted_d = sorted(d.items(), key=lambda x: x[1])
```

This will give you a list of tuples, sorted by the value of each tuple.

You can also use the `OrderedDict` class from the `collections` module to sort a dictionary by key or value. To do this, you can use the `sorted` function to create a sorted list of keys or values, and then use the `OrderedDict` constructor to create an `OrderedDict` from the sorted list.

For example:

```python
from collections import OrderedDict

d = {"a": 1, "b": 2, "c": 3}
sorted_d = OrderedDict(sorted(d.items(), key=lambda x: x[0]))
```

This will create an `OrderedDict` with the keys sorted in ascending order.

You can also use the `sort_by_key` and `sort_by_value` functions from the `dicttoolz` library to sort dictionaries by key or value, respectively.

```python
from dicttoolz import sort_by_key, sort_by_value

d = {"a": 1, "b": 2, "c": 3}
sorted_d = sort_by_key(d)
```

This will return a new dictionary with the keys sorted in ascending order.